Displacement Current

An electric field changing with time gives rise to a magnetic field, is a consequence of the _____ being a source of magnetic field.

List the consequences of the displacement current.

Displacement current is continuous:

Ampere's circuital law is given by:

Define ampere circuital law.

What is conventional electric current?

The charge of a parallel plate capacitor is varying as $q=q_0\mathrm{sin(}2\pi f\mathrm{t)}$. The plates are very large and close together (area$=A$, separation$=d$). Neglecting the edge effects, the displacement current through the capacitor is

Instantaneous displacement current of $1.0 \mathrm{A}$ in the space between the parallel plate of $1 \mathrm{\mu F}$ capacitor can be established by changing potential difference at a rate of

A capacitor is having a capacity of $2\mathrm{pF}$. Electric potential across the capacitor is changing with a rate of ${10}^{12} \mathrm{V}/\mathrm{s}$. The displacement current is:

A magnetic field can be produced by

Calculate the displacement current through a symmetrically drawn area $\frac{A}{4}$ between the plates of a parallel plate capacitor of area $A$ and plate separation $d$. It is given that the capacitor is charged by a constant current $i$.

Find the displacement current through the plates of a parallel plate capacitor if it is known that the charge on the plates vary as $q=q_0$$\sin 2\mathrm{\pi nt}$. Assume that the plates are very large and close together and neglect the edge effects.

In order to establish an instantaneous displacement current of $1 \mathrm{mA}$ in the space between the plates of $2 \mu \mathrm{F}$ parallel plate capacitor, the rate of change of potential difference is

Displacement current goes through the gap between the plates of a capacitor when the charge on the capacitor

The displacement current is

Displacement current is

The magnetic field between the plates of a capacitor when r > R is given by

In electromagnetic wave, according to Maxwell, changing electric field gives

A capacitor has a capacity of $2 \mathrm{pF}$. The electric field across the capacitor is changing with a value of ${10}^{12}\mathrm{ }\mathrm{V} {\mathrm{s}}^{-1}$. The displacement current is

A parallel plate capacitor is charged to $60 \mathrm{\mu C}$. Due to a radioactive source, the plate loses charge at the rate of $1.8\times {10}^{-8}\mathrm{ }\mathrm{C} {\mathrm{s}}^{-1}$. The magnitude of displacement current is